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Be able to use own encoder and decoder. #1080

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Be able to use own encoder and decoder. #1080

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b68b9b4
Be able to use own encoder and decoder.
noppefoxwolf Dec 12, 2019
867a0b0
Update Sources/CodableTransform.swift
noppefoxwolf Feb 3, 2020
10e5b25
Update Sources/CodableTransform.swift
noppefoxwolf Feb 3, 2020
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11 changes: 7 additions & 4 deletions Sources/CodableTransform.swift
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Expand Up @@ -33,8 +33,13 @@ open class CodableTransform<T: Codable>: TransformType {

public typealias Object = T
public typealias JSON = Any

public init() {}
private let encoder: JSONEncoder
private let decoder: JSONDecoder

public init(decoder: JSONDecoder = .init(), encoder: JSONEncoder = .init()) {
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Why you decided to create an initializer for these properties?

I think this development is unnecessary to use encoder and decoder because these properties aren't use anywhere except functions.

On the other hand some cases we don't need to create encoder or decoder.
For example; if data comes NULL in transformFromJSON (_ value:) -> Object? function returns immediately from guard statement and we don't create a decoder.

transformToJSON (_ value: ) -> JSON? has a same case, if value comes NULL we don't create encoder.

What do you think about this cases?

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We want to set options for JSONDecoder and JSONEncoder.
For example, cannot set dataDecodingStrategy by current code.

self.encoder = encoder
self.decoder = decoder
}

open func transformFromJSON(_ value: Any?) -> Object? {
var _data: Data? = nil
Expand All @@ -49,7 +54,6 @@ open class CodableTransform<T: Codable>: TransformType {
guard let data = _data else { return nil }

do {
let decoder = JSONDecoder()
let item = try decoder.decode(T.self, from: data)
return item
} catch {
Expand All @@ -62,7 +66,6 @@ open class CodableTransform<T: Codable>: TransformType {
return nil
}
do {
let encoder = JSONEncoder()
let data = try encoder.encode(item)
let dictionary = try JSONSerialization.jsonObject(with: data, options: .allowFragments)
return dictionary
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