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Avoid moving out of brace object in cs and ds #217

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25 changes: 22 additions & 3 deletions plugin/surround.vim
Expand Up @@ -92,7 +92,7 @@ function! s:process(string)
let m = matchstr(a:string,nr2char(i).'.\{-\}\ze'.nr2char(i))
if m != ''
let m = substitute(strpart(m,1),'\r.*','','')
let repl_{i} = input(substitute(m,':\s*$','','').': ')
let repl_{i} = input(match(m,'\w\+$') >= 0 ? m.': ' : m)
endif
endfor
let s = ""
Expand Down Expand Up @@ -394,6 +394,11 @@ function! s:dosurround(...) " {{{1
exe 'norm! dt'.char
else
exe 'norm! d'.strcount.'i'.char
" Note_issue215:
" at this point for [](){}<>, we usually expect cursor to be on the right
" brace. However that won't be the case if the right brace had a newline
" before it and the left brace had text afterward with no newline -- in
" that case, the cursor will be on the left brace. See issue 215.
endif
let keeper = getreg('"')
let okeeper = keeper " for reindent below
Expand All @@ -420,8 +425,22 @@ function! s:dosurround(...) " {{{1
exe 'norm! F'.char
exe 'norm! df'.char
else
" One character backwards
call search('\m.', 'bW')
" One character backwards, except if the cursor is now on the left brace.
" see Note_issue215.
let move_left = 1
let lefts = '[({<'
let rights = '])}>'
let left_i = match(lefts, char)
let right_i = match(rights, char)
if left_i != -1 || right_i != -1
let left = right_i != -1 ? lefts[right_i] : char
if getline('.')[col('.') - 1] == left
let move_left = 0
endif
endif
if move_left
call search('\m.', 'bW')
endif
exe "norm! da".char
endif
let removed = getreg('"')
Expand Down