fix: recursive resolve deps on create command graph

packages/nx/src/commands-runner/create-command-graph.ts

@@ -4,24 +4,48 @@ import { NxArgs } from '../utils/command-line-utils';
 import { output } from '../utils/output';
 import { CommandGraph } from './command-graph';
 
+/**
+ * Make structure { lib: [dep], dep: [dep1], dep1: [] } from projectName lib and projectGraph
+ * @param projectGraph
+ * @param projectName
+ * @param resolved reference to an object that will contain resolved dependencies
+ * @returns
+ */
+const recursiveResolveDeps = (projectGraph: ProjectGraph, projectName: string, resolved: Record<string, string[]>) => {
+  if (projectGraph.dependencies[projectName].length === 0) {
+    // no deps - no resolve
+    resolved[projectName] = []
+    return
+  }
+  // if already resolved - just skip
+  if (resolved[projectName]) {
+    return resolved[projectName]
+  }
+
+  // deps string list
+  const projectDeps = [
+    ...new Set(projectGraph.dependencies[projectName]
+      .map((projectDep) => projectDep.target)
+      .filter((projectDep) => projectGraph.nodes[projectDep])).values(),
+  ];
+
+  // define
+  resolved[projectName] = projectDeps;
+  if (projectDeps.length > 0) {
+    for (const dep of projectDeps) {
+      recursiveResolveDeps(projectGraph, dep, resolved)
+    }
+  }
+}
+
 export function createCommandGraph(
   projectGraph: ProjectGraph,
   projectNames: string[],
   nxArgs: NxArgs
 ): CommandGraph {
-  const dependencies: Record<string, string[]> = {};
+  const dependencies: Record<string, string[]> = {}
   for (const projectName of projectNames) {
-    if (projectGraph.dependencies[projectName].length >= 1) {
-      dependencies[projectName] = [
-        ...new Set(
-          projectGraph.dependencies[projectName]
-            .map((projectDep) => projectDep.target)
-            .filter((projectDep) => projectGraph.nodes[projectDep])
-        ).values(),
-      ];
-    } else {
-      dependencies[projectName] = [];
-    }
+    recursiveResolveDeps(projectGraph, projectName, dependencies)
   }
   const roots = Object.keys(dependencies).filter(
     (d) => dependencies[d].length === 0