Reflect.has fails to act as type guard (should act same as "in" operator)

[lukewlms]

TypeScript Version: ^3.4.0-dev.20190330

Search Terms:
Reflect.has
in operator

Code

const test1 = (a: { field: number } | {}) => (("field" in a) ? a.field : 0);

const test2 = (a: { field: number } | {}) => Reflect.has(a, "field") ? a.field : 0;

Expected behavior:
Both compile successfully. "in" operator acts as a type guard per #10485. Reflect.has should act the same as "in" operator here.

We'd like to use Reflect.has a lot more and this case holds us back. Thank you!

Actual behavior:
"in" operator line compiles; Reflect.has line does not compile. Error:

allPasos.ts:445:31 - error TS2339: Property 'field' does not exist on type '{} | { field: number; }'.
Property 'field' does not exist on type '{}'.

445 Reflect.has(a, "field") ? a.field : 0;

Playground Link:

https://goo.gl/2R4dkS

Related Issues:

#10485

[dragomirtitian]

This could be a definition of has that would work as you expect:

declare namespace Reflect {
  function has<T, K extends PropertyKey>(target: T, propertyKey: K): target is Extract<T, Record<K, any>>;
}
const test2 = (a: { field: number } | {}) => Reflect.has(a, 'field') ? a.field : a;

As a workaround you could add it yourself.

[lukewlms]

Looks like that does work as a stopgap! Thanks for the suggestion, added that in our custom types code.