Skip to content

Confusing enum reverse string lookup behaviour in strict mode #29094

@jleclanche

Description

@jleclanche

Summary

Code below.

Typescript in --strict mode will reject enum reverse lookups using arbitrary strings with this very confusing error message:

Element implicitly has an 'any' type because index expression is not of type 'number'.

A workaround is to cast the string to a subset of all possible enum keys but that's impractical with large enums (or is there an easy way to say "any key of enum X" in TS?).

My real world use case: I have a react app with a <select> filter on various items, and a bunch of <option> values, all of which are part of an integer enum. I have to use the string representation in the dom, so the state of the filter has to be the string representation. When I check the item's enum value I already know it can only be one of those enum members.

This report is three-fold:

  1. Is this behaviour intended? There are cases where it can definitely catch a reverse lookup that can fail.
  2. If it is intended, then what is the correct way to declare that the lookup will always be valid? let typeFilter: "FOO" | "BAR" = "FOO" is impractical and increases risk of errors.
  3. Regardless of the above, the error message should be fixed. The element highlighted (typeFilter) does not in fact have an "any" type, and Type[typeFilter] will not be any either (in fact, Type[typeFilter] as Type does not fix it). An error such as "Reverse lookup on enum Type may fail because typeFilter is of type 'string'" is much clearer already.

Details

TypeScript Version: 3.2.2

Search Terms: enum reverse string lookup

Code

// test.ts
// Compile with `tsc --strict test.ts`
export enum Type {
	FOO = 0,
	BAR = 1,
}

const Test = () => {
	// Change the following line to `let typeFilter: "FOO" | "BAR" = "FOO";` and it will work
	let typeFilter = "FOO";

	if (Type[typeFilter] != Type.FOO) {
		return;
	}
};

export default Test;

Actual behavior:

test.ts:9:11 - error TS7015: Element implicitly has an 'any' type because index expression is not of type 'number'.

9  if (Type[typeFilter] != Type.FOO) {
            ~~~~~~~~~~


Found 1 error.

Playground Link: Playground

Related Issues: Maybe #27297

Metadata

Metadata

Assignees

No one assigned

    Type

    No type

    Projects

    No projects

    Relationships

    None yet

    Development

    No branches or pull requests

    Issue actions