Remove SeqUtil.filterToSome #3077
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Slight refactoring. Seq.choose f is equivalent to Seq.map(f) |> SeqUtil.filterToSome
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Given that the build used to work but now doesn't, I'm going to go out on a limb and say that this build error is an MSBuild bug. |
jaredpar
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Nov 16, 2023
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Slight refactoring.
Seq.choose f is equivalent to Seq.map f |> SeqUtil.filterToSome