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Main3 #2

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21af9f5
finishing the tp adding conclusions
Noexperience-Team Oct 27, 2020
0cf1f5d
finishing the tp adding conclusions2
Noexperience-Team Oct 27, 2020
fcb8fd4
finishing the tp adding conclusions3
Noexperience-Team Oct 27, 2020
66c698d
finishing the tp adding conclusions3
Noexperience-Team Oct 27, 2020
e6a0199
new tp
Noexperience-Team Oct 28, 2020
70b5650
new tp2
Noexperience-Team Oct 28, 2020
caa1353
finishing work
Noexperience-Team Nov 5, 2020
15fcef6
finishing work1
Noexperience-Team Nov 5, 2020
ddb5455
still hand working
Noexperience-Team Nov 7, 2020
a9f3a3a
still hand working
Noexperience-Team Nov 7, 2020
ca28420
Create README.md
Noexperience-Team Nov 7, 2020
f59c057
Update README.md
Noexperience-Team Nov 7, 2020
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156 changes: 78 additions & 78 deletions .ipynb_checkpoints/Analyse_numerique_TP1-checkpoint.ipynb
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2 changes: 1 addition & 1 deletion README.md
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# Analyse_numeriqueTP
[![Binder](https://mybinder.org/badge_logo.svg)](https://mybinder.org/v2/gh/Noexperience-Team/Analyse_numeriqueTP/main)
[![Binder](https://mybinder.org/badge_logo.svg)](https://mybinder.org/v2/gh/Noexperience-Team/Analyse_numeriqueTP/main3)
1 change: 1 addition & 0 deletions requirement.txt
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numpy==1.17.4
798 changes: 798 additions & 0 deletions tp1/.ipynb_checkpoints/Analyse_numerique_TP1-checkpoint.ipynb
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116 changes: 63 additions & 53 deletions Analyse_numerique_TP1.ipynb → tp1/Analyse_numerique_TP1.ipynb
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"name": "stdout",
"output_type": "stream",
"text": [
"Requirement already satisfied: bigfloat in /home/bacemabr/anaconda3/envs/chatbot1/lib/python3.6/site-packages (0.4.0)\n",
"Requirement already satisfied: six in /home/bacemabr/anaconda3/envs/chatbot1/lib/python3.6/site-packages (from bigfloat) (1.13.0)\n",
"Note: you may need to restart the kernel to use updated packages.\n"
"\n"
]
}
],
"source": [
"pip install bigfloat"
"%load_ext watermark\n",
"%watermark --iversions\n",
"\n"
]
},
{
"cell_type": "code",
"execution_count": 2,
"execution_count": 28,
"metadata": {},
"outputs": [],
"source": [
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},
{
"cell_type": "code",
"execution_count": 3,
"execution_count": 29,
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},
{
"cell_type": "code",
"execution_count": 4,
"execution_count": 30,
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},
{
"cell_type": "code",
"execution_count": 5,
"execution_count": 31,
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"outputs": [
{
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{
"cell_type": "code",
"execution_count": 6,
"execution_count": 32,
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{
"cell_type": "code",
"execution_count": 7,
"execution_count": 33,
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},
{
"cell_type": "code",
"execution_count": 8,
"execution_count": 34,
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{
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},
{
"cell_type": "code",
"execution_count": 9,
"execution_count": 35,
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},
{
"cell_type": "code",
"execution_count": 10,
"execution_count": 36,
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{
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},
{
"cell_type": "code",
"execution_count": 11,
"execution_count": 37,
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},
{
"cell_type": "code",
"execution_count": 12,
"execution_count": 38,
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{
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{
"cell_type": "code",
"execution_count": 13,
"execution_count": 39,
"metadata": {},
"outputs": [
{
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},
{
"cell_type": "code",
"execution_count": 14,
"execution_count": 40,
"metadata": {},
"outputs": [
{
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},
{
"cell_type": "code",
"execution_count": 15,
"execution_count": 41,
"metadata": {},
"outputs": [],
"source": [
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},
{
"cell_type": "code",
"execution_count": 16,
"execution_count": 42,
"metadata": {},
"outputs": [
{
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"-0.5117446282927461"
]
},
"execution_count": 16,
"execution_count": 42,
"metadata": {},
"output_type": "execute_result"
}
Expand All @@ -465,11 +465,12 @@
]
},
{
"cell_type": "code",
"execution_count": null,
"cell_type": "markdown",
"metadata": {},
"outputs": [],
"source": []
"source": [
"#### g1'(x)<0 et |g1'(x)| <1 ==> existe un local dans [1,2] ==> la methode de point fixe converge totalement \n",
"### g1 est d'ordre de convergence au moin 2"
]
},
{
"cell_type": "markdown",
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},
{
"cell_type": "code",
"execution_count": 17,
"execution_count": 43,
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},
{
"cell_type": "code",
"execution_count": 18,
"execution_count": 44,
"metadata": {},
"outputs": [
{
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"-0.12723758423338585"
]
},
"execution_count": 18,
"execution_count": 44,
"metadata": {},
"output_type": "execute_result"
}
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},
{
"cell_type": "code",
"execution_count": 19,
"execution_count": 45,
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},
{
"cell_type": "code",
"execution_count": 20,
"execution_count": 46,
"metadata": {},
"outputs": [
{
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"-15.509675000000001"
]
},
"execution_count": 20,
"execution_count": 46,
"metadata": {},
"output_type": "execute_result"
}
Expand All @@ -570,24 +571,33 @@
]
},
{
"cell_type": "code",
"execution_count": null,
"cell_type": "markdown",
"metadata": {},
"outputs": [],
"source": []
"source": [
"$ g2(x)=\\sqrt{\\displaystyle\\frac{10}{4+x}}=x$<br/>\n",
"$ g2'(x)={\\displaystyle\\frac{-10}{(4+x)^2.2\\sqrt{\\displaystyle\\frac{10}{4+x}}}} $<br/>\n",
"$ g2'(1.365)={\\displaystyle\\frac{-10}{(4+1.365)^2.2\\sqrt{\\displaystyle\\frac{10}{4+1.365}}}}=0 $<br/>\n",
"##### |g2'(x)| < 1 ==> g2 converge\n",
"#### ==> g2 est d'ordre de convergence au moin 2<br/>\n",
"$ g2''(x)=\\displaystyle\\frac{-\\frac{100}{\\sqrt\\frac{10}{(4+x)}}+160\\sqrt\\frac{10}{(4+x)}+40*x\\sqrt\\frac{10}{(4+x)}}{(2(4+x)^2\\sqrt\\frac{10}{(4+x)})^2}$<br/>\n",
"$ g2''(1.365)=\\displaystyle\\frac{-\\frac{100}{\\sqrt\\frac{10}{(4+1.365)}}+160\\sqrt\\frac{10}{(4+1.365)}+40*1.365\\sqrt\\frac{10}{(4+1.365)}}{(2(4+1.365)^2\\sqrt\\frac{10}{(4+1.365)})^2} =0.03557434787513\\approx0 $<br/>\n",
"#### ==> g2 est d'ordre de convergence au moin 3 g2'(1.365)=g2''(1.365)=0"
]
},
{
"cell_type": "code",
"execution_count": null,
"cell_type": "markdown",
"metadata": {},
"outputs": [],
"source": []
"source": [
"$g3(x)=x-x^3-4x^2+10=x$<br/>\n",
"$g3'(x)=1-8*x-3*x^2$<br/>\n",
"$g3'(1.365)=1-8*1.365-3*1.365^2=-15.509675\\neq0$<br/>\n",
"#### |g3'(x)| > 1\n",
"### => g3 diverge"
]
},
{
"cell_type": "code",
"execution_count": null,
"cell_type": "markdown",
"metadata": {},
"outputs": [],
"source": []
},
{
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},
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"cell_type": "code",
"execution_count": 21,
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},
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"cell_type": "code",
"execution_count": 22,
"execution_count": 48,
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{
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},
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"cell_type": "code",
"execution_count": 23,
"execution_count": 49,
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{
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},
{
"cell_type": "code",
"execution_count": 24,
"execution_count": 50,
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{
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},
{
"cell_type": "code",
"execution_count": 60,
"execution_count": 51,
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},
{
"cell_type": "code",
"execution_count": 63,
"execution_count": 52,
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{
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{
"cell_type": "code",
"execution_count": 45,
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},
{
"cell_type": "code",
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{
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]
},
{
"cell_type": "code",
"execution_count": null,
"cell_type": "markdown",
"metadata": {},
"outputs": [],
"source": []
"source": [
"#### la methode de newton est une cas particulier de la methode de point fixe mais elle a un ordre de convergence superieur a celle de la methode de point fixe et meme de la methode de Dichotpmy . d'autre partie , la methode de point fixe provoque de problem on doit trouver les g(x)=x et verifier si ils converges ou diverges puis on va etudier leurs ordres de convergence . la methode de newton et la plus performante pour trouver une valeur aproxime a x0 pour que f(x0)=0 "
]
}
],
"metadata": {
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2 changes: 2 additions & 0 deletions tp1/README.md
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# Analyse_numeriqueTP
[![Binder](https://mybinder.org/badge_logo.svg)](https://mybinder.org/v2/gh/Noexperience-Team/Analyse_numeriqueTP/main)
6 changes: 6 additions & 0 deletions tp2/.ipynb_checkpoints/Untitled-checkpoint.ipynb
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{
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"nbformat": 4,
"nbformat_minor": 4
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"cells": [],
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