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An implementation for Median Maintenence Algorithm using heaps

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Median-Maintenence

An implementation for Median Maintenence Algorithm using heaps

The goal of this problem is to implement the "Median Maintenance" algorithm (covered in the Week 3 lecture on heap applications). The text file (Median.txt) contains a list of the integers from 1 to 10000 in unsorted order; you should treat this as a stream of numbers, arriving one by one. Letting xix_ixi​ denote the iiith number of the file, the kkkth median mkm_kmk​ is defined as the median of the numbers x1,…,xkx_1,\ldots,x_kx1​,…,xk​. (So, if kkk is odd, then mkm_kmk​ is ((k+1)/2)((k+1)/2)((k+1)/2)th smallest number among x1,…,xkx_1,\ldots,x_kx1​,…,xk​; if kkk is even, then mkm_kmk​ is the (k/2)(k/2)(k/2)th smallest number among x1,…,xkx_1,\ldots,x_kx1​,…,xk​.)

In the box below you should type the sum of these 10000 medians, modulo 10000 (i.e., only the last 4 digits). That is, you should compute (m1+m2+m3+⋯+m10000)mod10000(m_1+m_2+m_3 + \cdots + m_{10000}) \bmod 10000(m1​+m2​+m3​+⋯+m10000​)mod10000.

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An implementation for Median Maintenence Algorithm using heaps

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