- Build a class with an initialize method and use an
attr_accessor
You will write a program that, given a word and a list of possible anagrams, selects the correct one(s).
Your class, Anagram should take a word on initialization, and instances should respond to a match method that takes an array of possible anagrams. It should return all matches in an array. If no matches exist, it should return an empty array.
In other words, given: "listen" and %w(enlists google inlets banana) the program should return ["inlets"].
listen = Anagram.new("listen")
listen.match(%w(enlists google inlets banana))
# => ["inlets"]Top Tip: %w?(some words) is simply a shortcut for instantiating an array with items in it!
Once again, this lab is test-driven. Run the test suite to get started. Remember that you can use the learn/rspec --fail-fast option to run the tests only up until the first failure, in order to work progressively through the tests.
Write your solution in anagram.rb.
Hints:
- Use an
attr_accessorto create a setter and getter method for the word that the Anagram class instances are initialized with. - How will you determine if one word is an anagram for another?
- You'll need to iterate over the array of words that the
.matchmethod takes as an argument. You will compare each word of that array to the word that the Anagram class is initialized with. - To determine if they are anagrams, try determining if they are composed of the same letters. Remember that you can split a word into an array of letters using
some_word.split(""). You can compare two arrays using the==. For example:
- You'll need to iterate over the array of words that the
[1, 2, 3] == [1, 2, 3]
=> true
[1, 3, 2] == [1, 2, 3]
=> falseTwo arrays are equal if they contain the same elements, in the same order. Remember that you can .sort an arrays elements. This will help in your comparison:
[1, 3, 2].sort == [3, 2, 1].sort
=> trueView Anagram Detector on Learn.co and start learning to code for free.