add check_permutation.rs #711
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Codecov ReportAll modified and coverable lines are covered by tests ✅
Additional details and impacted files@@ Coverage Diff @@
## master #711 +/- ##
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Coverage 94.78% 94.79%
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Files 298 299 +1
Lines 22161 22188 +27
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+ Hits 21006 21033 +27
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vil02
requested changes
May 6, 2024
src/string/check_permutation.rs
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| //! Given two strings s1 and s2 consisting of lowercase letters. | |||
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What if they are not lowercase letters?
src/string/check_permutation.rs
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| s1.chars() | ||
| .all(|c| s1.matches(c).count() == s2.matches(c).count()) |
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What is the time complexity of this?
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With the help of a hash table to record the number of occurrences of a character and then compare the time complexity should be linear time.
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Given two strings s1 and s2.
Determine whether the characters of one of the strings can be rearranged to become another string.