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261. Graph Valid Tree.py
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261. Graph Valid Tree.py
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# Given n nodes labeled from 0 to n - 1 and a list of undirected edges (each edge is a pair of nodes), write a function to check whether these edges make up a valid tree.
# For example:
# Given n = 5 and edges = [[0, 1], [0, 2], [0, 3], [1, 4]], return true.
# Given n = 5 and edges = [[0, 1], [1, 2], [2, 3], [1, 3], [1, 4]], return false.
# Note: you can assume that no duplicate edges will appear in edges. Since all edges are undirected, [0, 1] is the same as [1, 0] and thus will not appear together in edges.
# Union find that two node belongs to one root and these two nodes are connected so it is a graph
class Solution(object):
def validTree(self, n, edges):
"""
O(N)
O(N)
:type n: int
:type edges: List[List[int]]
:rtype: bool
"""
group = [i for i in range(n)]
for e1,e2 in edges:
root1 = self.find(e1,group)
root2 = self.find(e2,group)
if root1 == root2:
return False
else:
group[root2] = root1
return len(edges) == n -1
def find(self, e ,group):
if e == group[e]:
return e
else:
return self.find(group[e], group)