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236. Lowest Common Ancestor of a Binary Tree.py
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236. Lowest Common Ancestor of a Binary Tree.py
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# Given a binary tree, find the lowest common ancestor (LCA) of two given nodes in the tree.
# According to the definition of LCA on Wikipedia: “The lowest common ancestor is defined between two nodes v and w as the lowest node in T that has both v and w as descendants (where we allow a node to be a descendant of itself).”
# _______3______
# / \
# ___5__ ___1__
# / \ / \
# 6 _2 0 8
# / \
# 7 4
# For example, the lowest common ancestor (LCA) of nodes 5 and 1 is 3. Another example is LCA of nodes 5 and 4 is 5, since a node can be a descendant of itself according to the LCA definition.
# Definition for a binary tree node.
# class TreeNode(object):
# def __init__(self, x):
# self.val = x
# self.left = None
# self.right = None
class Solution(object):
def lowestCommonAncestor(self, root, p, q):
"""
O(ST)
:type root: TreeNode
:type p: TreeNode
:type q: TreeNode
:rtype: TreeNode
"""
if not root:
return None
if root == p or root == q:
return root
left = self.lowestCommonAncestor(root.left,p,q)
right = self.lowestCommonAncestor(root.right,p,q)
if left and right:
return root
return left if left else right