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Auth is not done via rtsp://admin:12345@192.168.5.150, Only the RTSP path like "/user=^USER^&^PASS^=&stream" works.
So normal to view the stream in VLC, I would enter rtsp://192.168.5.150/user=^USER^&^PASS^=&stream.
I do not know details of RTSP. it could be that the server needs more parameters (e.g. as headers)?
I would try to get a normal client working with the target then remove what is unneeded and add what is necessary to hydra-rtsp.c ...
I do not know details of RTSP. it could be that the server needs more parameters (e.g. as headers)? ...
can you give me an example of a parameter (e.g. as headers) maybe i can help? Isnt the parmeter "RTSP/1.0 451 ERROR" what hydra reads as 404 if the password isnt found?
Auth is not done via rtsp://admin:12345@192.168.5.150, Only the RTSP path like "/user=^USER^&^PASS^=&stream" works.
So normal to view the stream in VLC, I would enter rtsp://192.168.5.150/user=^USER^&^PASS^=&stream.
When trying to hydra, I get "[ERROR] unknown authentication protocol" what is on line 138 here
https://github.com/vanhauser-thc/thc-hydra/blob/master/hydra-rtsp.c#L138
RTSP status 451 is "Parameter Not Understood" https://www.websitepulse.com/kb/rtsp_status_codes so with a guess, there needs to be some instructions on how to do deal with the RTSP 451?
However im unsure as i dont know what this format would look like on rtsp /user=^USER^&^PASS^=&stream
Arch Linux
9.5 dev
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