API call limit

[tczee36]

How to avoid the following error?

Traceback (most recent call last):
File "tweet.py", line 30, in
for tweet in tweets:
File "/usr/local/lib/python3.7/dist-packages/tweepy/cursor.py", line 49, in next
return self.next()
File "/usr/local/lib/python3.7/dist-packages/tweepy/cursor.py", line 197, in next
self.current_page = self.page_iterator.next()
File "/usr/local/lib/python3.7/dist-packages/tweepy/cursor.py", line 108, in next
data = self.method(max_id=self.max_id, parser=RawParser(), *self.args, **self.kargs)
File "/usr/local/lib/python3.7/dist-packages/tweepy/binder.py", line 250, in _call
return method.execute()
File "/usr/local/lib/python3.7/dist-packages/tweepy/binder.py", line 234, in execute
raise TweepError(error_msg, resp, api_code=api_error_code)
tweepy.error.TweepError: Twitter error response: status code = 429

thanks

[rohanvivek]

Add wait_on_rate_limit=True on the API call like this:

api = tweepy.API(auth, wait_on_rate_limit=True)
This will make the rest of the code obey the rate limit