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The standard deviation of the sampling distribution is equal to the standard error of the mean for n projectiles.
Currently, the SD of the sampling distribution is using the following formula: SD = $\sqrt{\sum(x_i - xbar)^2/n}$
The correct formula is: SD = $\sqrt{\sum(x_i - xbar)^2/(n - 1)}$
In these equations, $x_1$ refers to the mean of each sample, and $xbar$ refers to the mean of means. n is the sample size.
The values will be close, especially for larger n, but I'm noting here that the calculation is incorrect currently.
The text was updated successfully, but these errors were encountered:
@matthew-blackman will you please evaluate and take the first steps here?
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matthew-blackman
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The standard deviation of the sampling distribution is equal to the standard error of the mean for n projectiles.
Currently, the SD of the sampling distribution is using the following formula:$\sqrt{\sum(x_i - xbar)^2/n}$
SD =
The correct formula is:$\sqrt{\sum(x_i - xbar)^2/(n - 1)}$
SD =
In these equations,$x_1$ refers to the mean of each sample, and $xbar$ refers to the mean of means. n is the sample size.
The values will be close, especially for larger n, but I'm noting here that the calculation is incorrect currently.
The text was updated successfully, but these errors were encountered: