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'seaborn-whitegrid' is not a valid package style, path of style file #403

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saif-software-developer opened this issue Sep 26, 2023 · 0 comments

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@saif-software-developer

Traceback (most recent call last):
File "/Users/xxx/Documents/adtk-poc/venv/lib/python3.9/site-packages/matplotlib/style/core.py", line 137, in use
style = _rc_params_in_file(style)
File "/Users/xxx/Documents/adtk-poc/venv/lib/python3.9/site-packages/matplotlib/init.py", line 866, in _rc_params_in_file
with _open_file_or_url(fname) as fd:
File "/usr/local/Cellar/python@3.9/3.9.13_3/Frameworks/Python.framework/Versions/3.9/lib/python3.9/contextlib.py", line 119, in enter
return next(self.gen)
File "/Users/xxx/Documents/adtk-poc/venv/lib/python3.9/site-packages/matplotlib/init.py", line 843, in _open_file_or_url
with open(fname, encoding='utf-8') as f:
FileNotFoundError: [Errno 2] No such file or directory: 'seaborn-whitegrid'

OSError: 'seaborn-whitegrid' is not a valid package style, path of style file, URL of style file, or library style name (library styles are listed in style.available)

Code:

import pandas as pd
from adtk.data import validate_series
from adtk.visualization import plot

s_train = pd.read_csv("../resources/ec2_cpu_utilization_24ae8d.csv",
                      index_col= "timestamp", parse_dates= True)
s_train = validate_series(s_train)
print(s_train)

plot(s_train)
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