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No I don't want the brute force code, but your code is inefficient in that it uses 3 tries to actually get the correct pin. You only have to test twice:
[1234, 5678, 1337]
And to test do:
[1234, 5678]
If one of the pins works
[1234]
If both pins were incorrect it is the third.
Yeah I know it's one request under hundreds/thousands, but I needed to get that out of my system.
Thanks for the source thought.
The text was updated successfully, but these errors were encountered:
No I don't want the brute force code, but your code is inefficient in that it uses 3 tries to actually get the correct pin. You only have to test twice:
And to test do:
If one of the pins works
If both pins were incorrect it is the third.
Yeah I know it's one request under hundreds/thousands, but I needed to get that out of my system.
Thanks for the source thought.
The text was updated successfully, but these errors were encountered: