AC current coil #561
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I'm building a real Helmholtz coil that accepts DC - 1000 Hz AC input. Reactive impedances come into play. |
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Replies: 2 comments 1 reply
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Hi Danylo, This depends on what your aim is. Magpylib computes the magnetic field, given a current. if your current has a time-dependence, e.g. i(t) = i0 * sin(wt), then the magnetic field will be B(t) = B0 * sin(wt). The field B0 is the static field generated by the current i0. If you are interested in computing the coil impedances, Magpylib can help, but you have to make the computation by yourself. The impedance is a result of the coil self-interaction. This comes down to computing the flux through the coil, generated by an input current. For that Magpylib can help when combined with a numerical integrator, but it requires a lot of handwork. Does this answer your question ? sincerely, |
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i(t) is the current in the system. If you inject a current, the above relation will be correct - its simply the relation between current in the system and magnetic field generated. If you drive with a voltage, there will be a frequency dependent phase shift an amplitude modulation because of the frequency dependent impedance. To use Magpylib in the AC regime you have to do some hands-on modelling. sincerely, |
Beta Was this translation helpful? Give feedback.
i(t) is the current in the system. If you inject a current, the above relation will be correct - its simply the relation between current in the system and magnetic field generated. If you drive with a voltage, there will be a frequency dependent phase shift an amplitude modulation because of the frequency dependent impedance.
To use Magpylib in the AC regime you have to do some hands-on modelling.
sincerely,
michael