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https://datascienceschool.net/03%20machine%20learning/10.01%20%EB%A1%9C%EC%A7%80%EC%8A%A4%ED%8B%B1%20%ED%9A%8C%EA%B7%80%EB%B6%84%EC%84%9D.html
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안녕하세요 김도형 박사님, 질문이 있습니다. "선형판별함수"의 z와 mu의 관계에서 z=0 -> mu(x)=0.5 라고 한다면, "statsmodels 패키지의 로지스틱 회귀" 부분에서 z값의 부호를 나누는 기준값은 4.2382x + 0.2515=0 이 되어야 하지 않나요? 베르누이 분포의 모수인 mu(x)가 로지스틱 함수인 sigma(z)를 따르므로 sigma(z)가 예측 클래스를 구분하는 기준값인 0.5가 되려면 z=w^Tx=0이 아닐까 궁금합니다.
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6.1 로지스틱 회귀분석 — 데이터 사이언스 스쿨
https://datascienceschool.net/03%20machine%20learning/10.01%20%EB%A1%9C%EC%A7%80%EC%8A%A4%ED%8B%B1%20%ED%9A%8C%EA%B7%80%EB%B6%84%EC%84%9D.html
The text was updated successfully, but these errors were encountered: