01%20python/02.15%20%ED%8C%8C%EC%9D%B4%EC%8D%AC%EC%97%90%EC%84%9C%20%EB%82%A0%EC%A7%9C%EC%99%80%20%EC%8B%9C%EA%B0%84%20%EB%8B%A4%EB%A3%A8%EA%B8%B0

[utterances-bot]

2.15 파이썬에서 날짜와 시간 다루기 — 데이터 사이언스 스쿨

https://datascienceschool.net/01%20python/02.15%20%ED%8C%8C%EC%9D%B4%EC%8D%AC%EC%97%90%EC%84%9C%20%EB%82%A0%EC%A7%9C%EC%99%80%20%EC%8B%9C%EA%B0%84%20%EB%8B%A4%EB%A3%A8%EA%B8%B0.html

[scrawl-dev]

class input_birthday(object):

def __init__(self, birthday):
    self.birthday = birthday
    
    

def how_old(self):
    
    today = dt.datetime.now()
    birthday_date = dt.datetime.strptime(str(self.birthday),"%Y%m%d") ## int -> str 변환 후 str -> 날짜로 변환
    age = math.ceil((today - birthday_date).days/365)
    
    if today.month > birthday_date.month:
        age = age
        
        if today.month == birthday_date.month:
            
            if today.day > birthday_date.day:
                age = age
            
            else:
                age -= 1
        
    else:
        age -= 1
        
    print(age)

[scrawl-dev]

today = datetime.datetime.now()
birthday = datetime.datetime(2000, 7, 18)

next_birthday = birthday + relativedelta(year = today.year+1)
remain_day = next_birthday - today

print("다음 생일은 " + str(next_birthday.date()) + " 입니다")
print("생일까지 남은 일수 : " + str(remain_day.days) + "일")
print("생일까지 남은 분 : " + str(round(remain_day.total_seconds()/60,)) + "분")

[EulogiaKoine]

연습 문제 15.1

bday = dt.datetime.strptime('2004.6.4','%Y.%m.%d')
bday.strftime("%Y년 %m월 %d일 {0}요일").format('월.화.수.목.금.토.일'.split('.')[x.weekday()])

 

---

연습 문제 15.2

# param {datetime} bday
# returns {int} 실행 시각을 기준으로 한 만 나이
def calculateCurrentAge(bday):
    today = dt.datetime.now()
    y = today.year - bday.year
    if today.month < bday.month + (1 if today.day < bday.day else 0):
        return y - 1
    return y

 

---

연습 문제 15.3

# go away, clean code!
from datetime import datetime

# 다음 생일까지 남은 일수
def getRemainingDaysTillNextBDay(month, day):
    today = datetime.now()
    return (datetime.strptime(f'{today.year + (1 if today.month > month else 0)}.{month}.{day}','%Y.%m.%d') - today).days

# '내년' 생일까지 남은 일수
def getRemainingDaysTillNextBDayOnNextYear(month, day):
    today = datetime.now()
    return (datetime.strptime(f'{today.year + 1}.{month}.{day}','%Y.%m.%d') - today).days

# '내년' 생일까지 남은 분(minutes)
def getRemainingMinutesTillNextBDayOnNextYear(month, day):
    today = datetime.now()
    return round((datetime.strptime(f'{today.year + 1}.{month}.{day}','%Y.%m.%d') - today).total_seconds() / 60, 2)

 

---

연습 문제 15.4

# 한 번에 하기
# relativedelta의 months 값을 사용하지 않아서 이걸 썼다고 해도 되는 건지는 모르겠지만, 일단 사용했습니다
import datetime as dt
from dateutil.relativedelta import relativedelta

def isLeapYear(year):
    return (dt.datetime.strptime(f'{year}.2.1', '%Y.%m.%d') + relativedelta(days=28)).month == 2

[ZZoongss]

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31

# 위 코드의 min, max 아이디어를 사용하였음 # 부모 클래스의 매소드 코드를 재사용 가능하다는 클래스 상속의 장점을 이용하였음   # 부모 클래스 Car 생성 class Car(object):       def __init__(self):         self.speed = 0         self.max_speed = 160         self.accel = 20              def speed_up(self):         self.speed = min(self.max_speed, self.speed + self.accel)         print('speed:',self.speed)              def speed_down(self):         self.speed = max(0, self.speed - self.accel)         print('speed:',self.speed)   #자식 클래스 SportCar 생성 class SportCar(Car):     def __init__(self):         super(SportCar,self).__init__()         self.max_speed = 200         self.accel = 45          # 자식 클래스 Truck 생성 class Truck(Car):     def __init__(self):         super(Truck,self).__init__()         self.max_speed = 100         self.accel = 15 Colored by Color Scripter

cs

[woominKIM]

연습문제2.15.1

---

from datetime import datetime as dt
myBirth = dt(1998, 9, 1)
wkday_D = {
    0: "월요일",
    1: "화요일",
    2: "수요일",
    3: "목요일",
    4: "금요일",
    5: "토요일",
    6: "일요일",
}
print(myBirth.strftime("%Y년 %B월 %d일"), wkday_D[myBirth.weekday()])

연습문제2.15.2

---

from datetime import datetime as dt
myBirth=dt(1998,9,1)
curTime=dt.now()
age=curTime.year-myBirth.year if curTime.month>=myBirth.month&curTime.day>=myBirth.day else curTime.year-myBirth.year-1
print(age)

연습문제2.15.3

---

from datetime import datetime as dt
from datetime import timedelta as td
cur = dt.now()
nextBirth = dt(cur.year + 1, 6, 25)
diff = nextBirth - cur
print("내년 생일까지", diff.days, "일 남음")
print("내년 생일까지", diff.days * 1440 + int(diff.seconds / 60), "분 남음")

연습문제2.15.4

---

from datetime import datetime as dt
from dateutil.relativedelta import relativedelta as rd
t = dt(2000,2,1)
rt = rd(days=28)
print("윤년입니다") if (t+rt).day==29 else print("윤년이 아닙니다")