UDL Acting from Left Support - Case 2.ipynb

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   "source": [
    "# UDL Acting from Left Support - Case 2"
   ]
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   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "### In the case of the length of UDL (a) dispersion is more than (L/2) and also the center of span lies within the UDL distributed length in which the UDL dispersion length commences from left end support of the above span."
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 1,
   "metadata": {},
   "outputs": [],
   "source": [
    "from math import pow as power"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "Input Data:"
   ]
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  {
   "cell_type": "code",
   "execution_count": 2,
   "metadata": {},
   "outputs": [],
   "source": [
    "L = 8.725\n",
    "W = 18.5303\n",
    "a = 5.92\n",
    "b = 2.805\n",
    "d = 5.92"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "### M_AB"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 3,
   "metadata": {},
   "outputs": [
    {
     "data": {
      "text/plain": [
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      ]
     },
     "execution_count": 3,
     "metadata": {},
     "output_type": "execute_result"
    }
   ],
   "source": [
    "M_AB = W*power(a, 2)/(12*power(L, 2)) * (6*power(L, 2) - 8*a*L + 3*power(a, 2));\n",
    "M_AB"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "### M_BA"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 4,
   "metadata": {},
   "outputs": [
    {
     "data": {
      "text/plain": [
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      ]
     },
     "execution_count": 4,
     "metadata": {},
     "output_type": "execute_result"
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   ],
   "source": [
    "M_BA = W*power(a, 3)/(12*power(L, 2)) * (4*L - 3*a);\n",
    "M_BA"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "### RA_FE"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 5,
   "metadata": {},
   "outputs": [
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     "data": {
      "text/plain": [
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     },
     "execution_count": 5,
     "metadata": {},
     "output_type": "execute_result"
    }
   ],
   "source": [
    "RA_FE = W*a/(6*power(L, 3)) * (6*power(L, 3) - 6*L*power(a, 2) + 3*power(a, 3));\n",
    "RA_FE"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "### RB_FE"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 6,
   "metadata": {},
   "outputs": [
    {
     "data": {
      "text/plain": [
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     },
     "execution_count": 6,
     "metadata": {},
     "output_type": "execute_result"
    }
   ],
   "source": [
    "RB_FE = W*power(a, 3)/(12*power(L, 3)) * (12*L - 6*a);\n",
    "RB_FE"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "### MaxBM_FE"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 7,
   "metadata": {},
   "outputs": [
    {
     "data": {
      "text/plain": [
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     "execution_count": 7,
     "metadata": {},
     "output_type": "execute_result"
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   ],
   "source": [
    "MaxBM_FE = W/(24*L) * (4*power(a, 3) - 3*power(L, 3) + 12*a*b*L)\n",
    "MaxBM_FE"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "### RA_SS"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 8,
   "metadata": {},
   "outputs": [
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     "data": {
      "text/plain": [
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     "execution_count": 8,
     "metadata": {},
     "output_type": "execute_result"
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   ],
   "source": [
    "RA_SS = W*a/(2*L) * (2*L - a)\n",
    "RA_SS"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "### RB_SS"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 9,
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   "outputs": [
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     "execution_count": 9,
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     "output_type": "execute_result"
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   ],
   "source": [
    "RB_SS = W*power(a, 2)/(2*L)\n",
    "RB_SS"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "### MaxBM_SS"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 10,
   "metadata": {},
   "outputs": [
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     "data": {
      "text/plain": [
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     },
     "execution_count": 10,
     "metadata": {},
     "output_type": "execute_result"
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   ],
   "source": [
    "MaxBM_SS = W/8 * (-2*power(a, 2) + 4*a*L - power(L, 2))\n",
    "MaxBM_SS"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": null,
   "metadata": {},
   "outputs": [],
   "source": []
  }
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