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find-words-that-can-be-formed-by-characters_1160.py
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find-words-that-can-be-formed-by-characters_1160.py
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# You are given an array of strings words and a string chars.
# A string is good if it can be formed by characters from chars (each character can only be used once).
# Return the sum of lengths of all good strings in words.
# Example 1:
# Input: words = ["cat","bt","hat","tree"], chars = "atach"
# Output: 6
# Explanation: The strings that can be formed are "cat" and "hat" so the answer is 3 + 3 = 6.
# Example 2:
# Input: words = ["hello","world","leetcode"], chars = "welldonehoneyr"
# Output: 10
# Explanation: The strings that can be formed are "hello" and "world" so the answer is 5 + 5 = 10.
# Constraints:
# 1 <= words.length <= 1000
# 1 <= words[i].length, chars.length <= 100
# words[i] and chars consist of lowercase English letters.
# ---------------------------------------Runtime 273 ms Beats 10.9% Memory 16.9 MB Beats 13.86%---------------------------------------
from typing import List
from collections import Counter
class Solution:
def countCharacters(self, words: List[str], chars: str) -> int:
res = 0
counter_chars = Counter(chars)
for word in words:
count_word = Counter(word)
if (counter_chars & count_word) == count_word:
res += len(word)
return res