lpcc same as lpc

[0viAB]

Hi! I noticed that LPCC function returns the same result as LPC function, despite the first coefficient which is calculated as a log. I looked at the code and I think the problem is intializing the c vector with zeros, because when the formula is applied, the c[k] is always 0, so it's adding 0 to the LPC coefficient.

[SuperKogito]

#68 introduced initialisation with ones which solves this