Strange behavior after defining show()

[dinurp]

I was watching the video [Rationale Behind Julia and the Vision] http://www.youtube.com/watch?v=02U9AJMEWx0) trying to do the same in REPL at the same time. I noticed a strange behavior. Can someone please explain this?

after
julia> importall Base
julia> type ModInt{n} <: Integer
k::Int
ModInt(k) = new(mod(k,n))
end

when i entered
julia> a = ModInt{11}(2011)

when I entered
julia> show{n}(io::IO, k::ModInt{n}) = print(io, "$(k.k) mod $n")
all the definitions of show got listed.

now,when i entered
julia> a
ModInt{11}(9)

but when I enter
julia> print(a)
9 mod 11

but when I entered
julia> (a,a)
(9 mod 11,9 mod 11)

strangely
*julia> * c = ModInt{13}(45)
6 mod 13

but
julia> ModInt{11}(45)
ModInt{11}(1)

julia> ModInt{12}(45)
9 mod 12

Version: (julia-0.2pre-dbac83fb44-WINNT-i686.zip)
Version 0.2.0
dbac83f-WINNT-i686 (2013-06-12 15:23:39)
i686-w64-mingw32

[quinnj]

I don't remember when this changed, but the current method to overload for custom types is repl_show. We should make sure the documentation is accurate on this.

[johnmyleswhite]

You don't need to edit repl_show() most of the time: just show(io::IO, o::Object).

-- John

On Jun 28, 2013, at 9:14 AM, Jacob Quinn notifications@github.com wrote:

I don't remember when this changed, but the current method to overload for custom types is repl_show. We should make sure the documentation is accurate on this.

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Reply to this email directly or view it on GitHub.

[StefanKarpinski]

This is just an artifact of having already generated code for ModInt{11} before defining a specialized show. Since ModInt{12} is a different type, it gets its own code. Dup of #265.