if (and) with indented condition list

[bbrk24]

This gives a ParseError saying it expected a ::= where I have undefined:

        return if (and)
            upper.test exactOrAny.toString()
            lower.test exactOrAny.toString()
        then exactOrAny
        else undefined

If I oblige and change the last line to else ::= undefined, the result is not remotely what I wanted out of this expression (and in fact not valid TS):

        return (((a,b) => a&&b)?(
            upper.test(exactOrAny.toString()),
            lower.test(exactOrAny.toString())):void 0)
        then(exactOrAny)
        type else = undefined

I was hoping to get this:

return (upper.test(exactOrAny.toString()) && lower.test(exactOrAny.toString())) ? exactOrAny : undefined;

[edemaine]

Currently we forbid indented function application in an if condition, to avoid confusion with the usual "then" block. For example:

if foo
  bar
↓↓↓
if (foo) {
  bar
}
// NOT
if foo(
  bar
)

Perhaps we could make an exception when there's an explicit then. Meanwhile, you can wrap your condition in parentheses...

[bbrk24]

Just ran into this in a different context:

return false unless (and)
  ...

[edemaine]

Ah, adding support for indented function application to postfix if/then should be easier to add. (...unless I'm missing some ambiguity...)