Is it possible to include an exception to a glob exclusion?

[jpmor]

If I have a directory foo/ with a bunch of subdirectories, one of which is bar/... Is there a way to ensure bar/ is the only directory searched in foo/ via globbing?

Maybe something like: -g '!foo/!(bar/)'

To make the example more concrete, I am working with a code base with many directories in vendor/, and I want to exclude all of them except one or two from searches.

Thanks!

[BurntSushi]

@jpmor The simplest solution would be to just specify those directories to search, e.g., -g 'foo/bar/**'. But if that doesn't work, then you could do -g 'foo/**' -g '!foo/*' -g 'foo/bar' or something like that. But the simplest way to express "search many directories but exclude all except one or two" is to just specify the one or two things you want to search.

[jpmor]

@BurntSushi - thanks for the quick response! Making sure things outside of foo are also searched was the complicating factor, but based on your suggestion I've tried:

-g '**' -g '!foo/*' -g 'foo/bar'

That's giving me exactly what I was looking for, thank you!

[jpmor]

Actually, here's an (uglier) but even better option:

rg -g '!{'"$(echo foo/!(bar) | sed 's/ /,/g')"'}/**'

This just shifts the matching onto bash extglob or zsh extended_glob etc.

This is much faster that having an initial -g '**'.