Help, Schema types isn't having types applied (typescript)

[ShadiestGoat]

Heya! I used to use 5.11.12, and what I did work. I checked the change log, and in 5.11.15, mongoose was updated in regards to types, but this breaks a lotta stuff. Now, I could just use an old version or something, but that's for the weak.

Anyways, I have this in my previous works:

export interface IUser { 
    username: string,
    password: string,
    email:string
    id: string,
} 

export type SH = IUser & Document 

const SH = new Schema({
    username: {},
    password: String,
    email: String,
    id: String
})

export const mod:Model<SH> = model<SH>("AuthUser", SH)

Right, so that's great, but now, due to the absence of typescript docs, I can't figure out what to do, since it doesn't give type help, so I am assuming I'm doing something wrong? Thank you!

Edit:

So, I decided to deep dive straight into the types document in my local installation. After searching for quite a bit, I've ended up with the following code

export interface IUser { 
    username: string,
    password: string,
    email:string
    id: string,
}

export type SH = IUser & Document 

const SH = new Schema<SH, Model<SH>, SH>({
    username: {unique: true, type: String},
    email: String,
    password: String,
    id: String,
})

Now, the problem there is that the username is actually giving of an error. I dug for the causes of the error, and found that its calling the type SchemaDefinition<The interface SH, without stuff like _id, __v, or function names>. Then, since T isn't undefined, it goes into { [path in keyof T]?: SchemaDefinitionProperty<T[path]>; }. This is all good, but here is where the problem lies.
I am looking for SchemaTypeOptions for the property username, but I don't see a way of getting it. Regardless, I think I will open an issue for this, since I don't see a way of getting to it, and suspect it may actually be impossible, if using a predetermined interface. I even tried to type SH = Omit<IUser, "username"> & Document & {username: (black magic)}, so that's the end of that.

To clarify, the solution to the original question is that you needed to do Schema<SH, Model<SH>, SH>, where only the last one actually matters

[ShadiestGoat]

Solved,

To clarify, the solution to the original question is that you needed to do Schema<SH, Model, SH>, where only the last one actually matters