Value be Something OR SomethingElse

[alanjames1987]

I'm trying to test that a value is one value or another. In either case it's considered passing but I have not been able to figure out how to test for this.

Does expect.js support this sort of assertion and if not how should I go about testing for it?

[alanjames1987]

I know I can use a ternary to select the correct value before giving it to expect, but that seems sloppy to me if expect supports this already.

[janmarek]

What about

expect(value === 1 || value === 'abcd').to.be(true);

?

[alanjames1987]

In my tests I have currently written something like that, but the logical operator was in the .be(...) area.

expect(actualValue).to.be(testValue === 1 || testValue === 'abcd');

This works but it was ugly. I was looking for something better.

[panstav]

I usually declare variables for each such option, especially when I have >= 3 of those. So for example you could write:

var first = testValue === 1;
var second = testValue === 'abcd';

expect(actual).to.be(first || second);

[ghost]

 expect([1, 'abcd']).to.contain(actualValue)

[rafis]

Another variant:

expect.Assertion.prototype.stringOrArrayOfStrings = function() {
    var ok;
    if (typeof this.obj == 'string') {
        ok = true;
    } else if (this.obj instanceof Array) {
        ok = true;
        for(var i = 0; i < this.obj.length; ++i) {
            if (typeof this.obj[i] != 'string') {
                ok = false;
                break;
            }
        }
    } else {
        ok = false;
    }
    this.assert(ok, function() {
        return 'expected ' + expect.stringify(this.obj) + ' to be a string or an array of strings';
    }, function() {
        return 'expected ' + expect.stringify(this.obj) + ' to not be a string or an array of strings';
    });
};
expect(config.session.secret).to.be.stringOrArrayOfStrings();