how to find subarray?

[WingDust]

Given the array

y =[0,0,0,10,1,10,76,178,1020,0,10,0,229,2,2,0,0,178,1020,10,0,178,0,2,127,76,1020,178,178,1020,0,1020,0,76,1020,130,0,0]

to find all subarrays that start and end with 0 and must contain non-zero numbers in between.

Return the start and end indices of these subarrays.

[bunglegrind]

quick and dirty

const isStart = ([f, s]) => f === 0 && s !== 0;
const isEnd = ([f, s]) => f !== 0 && s === 0;
const reduceIndexed = R.addIndex(R.reduce);

reduceIndexed((acc, item, index)  =>  (
    isStart(item)
    ? [...acc, index]
    : (
       isEnd(item)
       ?  [...acc, index + 1]
       : acc
      )
), [], R.aperture(2, y));

REPL

I suppose a better solution is achievable by employing transducers