How to start a program with args #1257
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fish-python
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I'm a fish on pywinauto,when I try to start a program on windows using pywinauto,if I use path "c:/path/aaa.exe",I found the program can't start with quick login,because the user info can't use in program,so I open the strartup,Ifound the program path is like "c:/path/aaa.exe ver=1 "0711296a70d754486417e81e747c6d7acb0f11f83652de41a84a4633a2638518da4c55dc3e51a40984f2386f906302feb61f1ff30c0589037227d7939dcd68e8128836f8dc", so how can I write program in app.start? thank you for your answer,good time
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