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把问题弄简单才是人们所追求的 #1

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VectorWen opened this issue Apr 20, 2017 · 2 comments
Open

把问题弄简单才是人们所追求的 #1

VectorWen opened this issue Apr 20, 2017 · 2 comments

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@VectorWen
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VectorWen commented Apr 20, 2017

继承ViewGroup 定义新的布局文件不是人们所熟悉的,大部分人会被你这个继承吓走了,如何深入了解你的实现,如何更好地去使用呢?

从基本布局入手FrameLayout 才是最好的选择,使用margin 来定位每个View。

   /**
     * 计算显示9 张图片每一张图片的margin
     * @return [marginLeft, marginRight]
     */
    public static int[] getCircleImageMargin(int imageSize,int count) {

        //计算坐标
        int x, y;

        switch (count) {
            case 0:
            case 1:
            case 2:
                y = 0;
                break;
            case 3:
            case 4:
            case 5:
                y = 1;
                break;
            default:
                y = 2;

        }

        switch (count) {
            case 0:
            case 3:
            case 6:
                x = 0;
                break;
            case 1:
            case 4:
            case 7:
                x = 1;
                break;
            default:
                x = 2;

        }

        int left = (imageSize + DimenUtils.dip2px(App.sInstance, 2)) * x;
        int top = (imageSize + DimenUtils.dip2px(App.sInstance, 2)) * y;
        return new int[]{left, top};
    }
@fmliqi
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fmliqi commented Dec 21, 2018

继承ViewGroup 定义新的布局文件不是人们所熟悉的,大部分人会被你这个继承吓走了,如何深入了解你的实现,如何更好地去使用呢?

从基本布局入手FrameLayout 才是最好的选择,使用margin 来定位每个View。

   /**
     * 计算显示9 张图片每一张图片的margin
     * @return [marginLeft, marginRight]
     */
    public static int[] getCircleImageMargin(int imageSize,int count) {

        //计算坐标
        int x, y;

        switch (count) {
            case 0:
            case 1:
            case 2:
                y = 0;
                break;
            case 3:
            case 4:
            case 5:
                y = 1;
                break;
            default:
                y = 2;

        }

        switch (count) {
            case 0:
            case 3:
            case 6:
                x = 0;
                break;
            case 1:
            case 4:
            case 7:
                x = 1;
                break;
            default:
                x = 2;

        }

        int left = (imageSize + DimenUtils.dip2px(App.sInstance, 2)) * x;
        int top = (imageSize + DimenUtils.dip2px(App.sInstance, 2)) * y;
        return new int[]{left, top};
    }

麻烦大哥写个能用的,wtf!

@EmMper
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EmMper commented Jan 18, 2019

...
不知道该怎么吐槽了
给您劈个叉吧

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