应用层，类的非静态函数不能使用，目前仅静态函数可用

[dbdxnuliba]

测试例程如下：
class A {
public:
static int Afun(int n = 0) {
std::cout << n << " hello, Afun ! " << std::this_thread::get_id() << std::endl;
return n;
}

void Cfun(void) {
    std::cout <<  "  hello, Cfun !  "<< "mem_a :"<<mem_a <<"  " << std::this_thread::get_id() << std::endl;
    return ;
}

private:
int mem_a=0;
};
void test_thread_pool()
{
// Create pool with 3 threads,max_thr_num:100
//同时存活的线程的最小数量3,同时存活的线程的最大数量100
ThreadPool pool(1,2);

// Initialize pool
pool.init();

std::cout << "main thread id :"<<std::this_thread::get_id()<< std::endl;

 std::future<int> gg = pool.submit(A::Afun, 9999);//静态函数成功
 A A_obj;
std::future<int> hh = pool.submit(A_obj.Cfun,); //非静态函数不成功

}

: error: invalid use of non-static member function
std::future hh = pool.submit(A_obj.Cfun);
^

[dbdxnuliba]

经过查找资料可以这么实现，强制转换成员函数为普通函数
A A_obj;
typedef void* (FUNC)(void,int);
//FUNC callback = (FUNC)&A::Cfun;//强制转换func()的类型
FUNC callback = (FUNC)&A::Cfun;//强制转换func()的类型
pool.submit(callback,&A_obj,1);

[chanwoood]

可以这样写，一步到位：pool.submit(std::bind(&A::func, A_obj))

经过查找资料可以这么实现，强制转换成员函数为普通函数 A A_obj; typedef void* (FUNC)(void,int); //FUNC callback = (FUNC)&A::Cfun;//强制转换func()的类型 FUNC callback = (FUNC)&A::Cfun;//强制转换func()的类型 pool.submit(callback,&A_obj,1);

[dbdxnuliba]

厉害