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The function patition for quickSort can't support array which has duplicates. #202

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SikyChen opened this issue Jun 15, 2022 · 0 comments

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@SikyChen
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SikyChen commented Jun 15, 2022

It is a good way to patition a deduplicated array , but if the unsorted array is [1,2,3,4,4,4,2,4,4,6,7], the function can't move 2 to front.

I'd like to write a patition function like this:

function partition(array, left, right, compareFn) {
  const pivot = array[Math.floor((right + left) / 2)];
  let l = left;
  let r = right;
  let i = left;

  while (i <= r) {
    if (compareFn(array[i], pivot) === Compare.LESS_THAN) {
      swap(array, i, l);
      i++;
      l++;
    }
    else if (compareFn(array[i], pivot) === Compare.BIGGER_THAN) {
      swap(arr, i, r);
      r--;
    }
    else {
      i++;
    }
  }

  // return [l, r];
  return l;
}

PS:I learned a lot from your book, thank you~

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