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无法支持subType带有wildcard的情况 #5

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halflife3 opened this issue May 12, 2018 · 0 comments

halflife3 commented May 12, 2018

例如要build这个:java.util.Map<? extends java.lang.Comparable<? super java.lang.Number>, java.lang.String>

"? extends java.lang.Comparable" 这部分因为带有wildcard, 所以TypeBuilder的beginSubType方法无法支持

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