If i use WHILE (1), waiting for the serial port data will cause blocking, how to solve this problem?

[zhang402368157]

If i use WHILE (1), waiting for the serial port data will cause blocking, how to solve this problem?

Attached code:
while(1)
do

str = uart.getchar( 0 )

if(str == '\a')
then
break
else
uart.write( 0, str)
end

end

[gabrield]

str = uart.getchar( id, [timeout], [timer_id] ) Read a single character from the serial port *Arguments*: - *id* - the ID of the serial port - *timeout (optional)* - timeout of the operation, can be either *uart.NO_TIMEOUT* or 0 for non-blocking operation, *uart.INF_TIMEOUT* for blocking operation, or a positive number that specifies the timeout in microseconds. The default value of this argument is *uart.INF_TIMEOUT*. - *timer_id (optional)* - the ID of the timer used for measuring the timeout. If not specified it defaults to the system timer <http://www.eluaproject.net/doc/v0.9/en_arch_platform_timers.html#the_system_timer> . Take a look at the second argument: timeout ( - *uart.NO_TIMEOUT*) ;) Le lun. 16 juil. 2018 à 23:50, zhang402368157 <notifications@github.com> a écrit :

…

If i use WHILE (1), waiting for the serial port data will cause blocking, how to solve this problem? Attached code: while(1) do str = uart.getchar( 0 ) if(str == '\a') then break else uart.write( 0, str) end end — You are receiving this because you are subscribed to this thread. Reply to this email directly, view it on GitHub <#140>, or mute the thread <https://github.com/notifications/unsubscribe-auth/AANAZZ7iqQY3xNLJXOpF8PWRCD0mA17Xks5uHVENgaJpZM4VSGVC> .

-- Gabriel Duarte Rio de Janeiro / RJ http://genericdev.wordpress.com/

[zhang402368157]

Another question,whether the serial port can receive by interrupt ?

[gabrield]

Virtually, yes. Take a look again at the documentation: http://www.eluaproject.net/doc/v0.9/en_inthandlers.html :) Le dim. 22 juil. 2018 à 23:28, zhang402368157 <notifications@github.com> a écrit :

…

Another question,whether the serial port can receive by interrupt ? — You are receiving this because you commented. Reply to this email directly, view it on GitHub <#140 (comment)>, or mute the thread <https://github.com/notifications/unsubscribe-auth/AANAZULv15YW6ygKLKT0RZSp7blGLimoks5uJTTNgaJpZM4VSGVC> .

-- Gabriel Duarte Rio de Janeiro / RJ http://genericdev.wordpress.com/