HiveCreateTableStatement的CLUSTERED BY ( ..) INTO n BUCKETS 输出不符合语法规则

[niegl]

dbtype: hive
duird version: all version
error sql: CREATE TABLE db.route(
od_id string COMMENT 'OD',
data_dt string COMMENT 'data date')
CLUSTERED BY (
od_id)
INTO 8 BUCKETS
ROW FORMAT SERDE
'org.apache.hadoop.hive.ql.io.orc.OrcSerde'
STORED AS INPUTFORMAT
'org.apache.hadoop.hive.ql.io.orc.OrcInputFormat'
OUTPUTFORMAT
'org.apache.hadoop.hive.ql.io.orc.OrcOutputFormat';
error info: 没有错误，但是HiveCreateTableStatement的输出不符合语法规则。

根据hive的建表语法：
CREATE [TEMPORARY] [EXTERNAL] TABLE [IF NOT EXISTS] [db_name.]table_name -- (Note: TEMPORARY available in Hive 0.14.0 and later)
[(col_name data_type [column_constraint_specification] [COMMENT col_comment], ... [constraint_specification])]
[COMMENT table_comment]
[PARTITIONED BY (col_name data_type [COMMENT col_comment], ...)]
[CLUSTERED BY (col_name, col_name, ...) [SORTED BY (col_name [ASC|DESC], ...)] INTO num_buckets BUCKETS]
...

当语句为：CREATE TABLE db.route(
od_id string COMMENT 'OD',
data_dt string COMMENT 'data date')
CLUSTERED BY (
od_id)
INTO 8 BUCKETS
ROW FORMAT SERDE
'org.apache.hadoop.hive.ql.io.orc.OrcSerde'
STORED AS INPUTFORMAT
'org.apache.hadoop.hive.ql.io.orc.OrcInputFormat'
OUTPUTFORMAT
'org.apache.hadoop.hive.ql.io.orc.OrcOutputFormat'; 时，
druid解析对象为HiveCreateTableStatement，但是druid输出为
CREATE TABLE db.route(
od_id string COMMENT 'OD',
data_dt string COMMENT 'data date')
CLUSTERED BY (
od_id)
ROW FORMAT SERDE
INTO 8 BUCKETS
...
';

问题代码在类SQLASTOutputVisitor->printCreateTable(HiveCreateTableStatement x, boolean printSelect) 函数中的以下代码：
List clusteredBy = x.getClusteredBy();
if (clusteredBy.size() > 0) {
println();
print0(ucase ? "CLUSTERED BY (" : "clustered by (");
printAndAccept(clusteredBy, ",");
print(')');
}

没有将bucket部分的解析放到一起，而是将bucket部分放到了后面
int buckets = x.getBuckets();
if (buckets > 0) {
println();
print0(ucase ? "INTO " : "into ");
print(buckets);
print0(ucase ? " BUCKETS" : " buckets");
}